Base | Representation |
---|---|
bin | 101111001011101000… |
… | …011010111011010001 |
3 | 11211202122122000110102 |
4 | 233023220122323101 |
5 | 1312223204324103 |
6 | 35135013142145 |
7 | 3442266326654 |
oct | 571350327321 |
9 | 154678560412 |
10 | 50661011153 |
11 | 1a537902565 |
12 | 999a32a955 |
13 | 4a149aa89c |
14 | 264843989b |
15 | 14b7914e88 |
hex | bcba1aed1 |
50661011153 has 2 divisors, whose sum is σ = 50661011154. Its totient is φ = 50661011152.
The previous prime is 50661011113. The next prime is 50661011173. The reversal of 50661011153 is 35111016605.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28719403024 + 21941608129 = 169468^2 + 148127^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50661011153 is a prime.
It is not a weakly prime, because it can be changed into another prime (50661011113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25330505576 + 25330505577.
It is an arithmetic number, because the mean of its divisors is an integer number (25330505577).
Almost surely, 250661011153 is an apocalyptic number.
It is an amenable number.
50661011153 is a deficient number, since it is larger than the sum of its proper divisors (1).
50661011153 is an equidigital number, since it uses as much as digits as its factorization.
50661011153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 29.
Adding to 50661011153 its reverse (35111016605), we get a palindrome (85772027758).
The spelling of 50661011153 in words is "fifty billion, six hundred sixty-one million, eleven thousand, one hundred fifty-three".
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