Base | Representation |
---|---|
bin | 1001011100100110… |
… | …00011011100000011 |
3 | 111002110022202202011 |
4 | 10232103003130003 |
5 | 40341324322201 |
6 | 2155132233351 |
7 | 236452600225 |
oct | 45623033403 |
9 | 14073282664 |
10 | 5071714051 |
11 | 2172939918 |
12 | b9660b857 |
13 | 62a97a641 |
14 | 36180c415 |
15 | 1ea3c0151 |
hex | 12e4c3703 |
5071714051 has 2 divisors, whose sum is σ = 5071714052. Its totient is φ = 5071714050.
The previous prime is 5071714007. The next prime is 5071714093. The reversal of 5071714051 is 1504171705.
It is a happy number.
5071714051 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5071714051 - 225 = 5038159619 is a prime.
It is a super-2 number, since 2×50717140512 = 51444566830221661202, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5071714451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2535857025 + 2535857026.
It is an arithmetic number, because the mean of its divisors is an integer number (2535857026).
Almost surely, 25071714051 is an apocalyptic number.
5071714051 is a deficient number, since it is larger than the sum of its proper divisors (1).
5071714051 is an equidigital number, since it uses as much as digits as its factorization.
5071714051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4900, while the sum is 31.
The square root of 5071714051 is about 71215.9676687750. The cubic root of 5071714051 is about 1718.1124564596.
Adding to 5071714051 its reverse (1504171705), we get a palindrome (6575885756).
The spelling of 5071714051 in words is "five billion, seventy-one million, seven hundred fourteen thousand, fifty-one".
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