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50741220143 = 311636813553
BaseRepresentation
bin101111010000011010…
…011001001100101111
311211222020120001111202
4233100122121030233
51312404223021033
635151000240115
73444262153265
oct572032311457
9154866501452
1050741220143
111a579106789
129a0117003b
134a284b2123
142654d58435
1514be9aa8e8
hexbd069932f

50741220143 has 4 divisors (see below), whose sum is σ = 52378033728. Its totient is φ = 49104406560.

The previous prime is 50741220139. The next prime is 50741220149. The reversal of 50741220143 is 34102214705.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50741220143 - 22 = 50741220139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50741220149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 818406746 + ... + 818406807.

It is an arithmetic number, because the mean of its divisors is an integer number (13094508432).

Almost surely, 250741220143 is an apocalyptic number.

50741220143 is a deficient number, since it is larger than the sum of its proper divisors (1636813585).

50741220143 is a wasteful number, since it uses less digits than its factorization.

50741220143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1636813584.

The product of its (nonzero) digits is 6720, while the sum is 29.

Adding to 50741220143 its reverse (34102214705), we get a palindrome (84843434848).

The spelling of 50741220143 in words is "fifty billion, seven hundred forty-one million, two hundred twenty thousand, one hundred forty-three".

Divisors: 1 31 1636813553 50741220143