Base | Representation |
---|---|
bin | 101111010010001001… |
… | …101011100000011101 |
3 | 11212001021110012022021 |
4 | 233102021223200131 |
5 | 1312434210034432 |
6 | 35153521420141 |
7 | 3445065135553 |
oct | 572211534035 |
9 | 155037405267 |
10 | 50770393117 |
11 | 1a593621884 |
12 | 9a0aa9a651 |
13 | 4a31557842 |
14 | 2658b8dbd3 |
15 | 14c231e697 |
hex | bd226b81d |
50770393117 has 2 divisors, whose sum is σ = 50770393118. Its totient is φ = 50770393116.
The previous prime is 50770393067. The next prime is 50770393123. The reversal of 50770393117 is 71139307705.
50770393117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49455532996 + 1314860121 = 222386^2 + 36261^2 .
It is a cyclic number.
It is not a de Polignac number, because 50770393117 - 27 = 50770392989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50770393187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25385196558 + 25385196559.
It is an arithmetic number, because the mean of its divisors is an integer number (25385196559).
Almost surely, 250770393117 is an apocalyptic number.
It is an amenable number.
50770393117 is a deficient number, since it is larger than the sum of its proper divisors (1).
50770393117 is an equidigital number, since it uses as much as digits as its factorization.
50770393117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 138915, while the sum is 43.
The spelling of 50770393117 in words is "fifty billion, seven hundred seventy million, three hundred ninety-three thousand, one hundred seventeen".
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