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508002875249 is a prime number
BaseRepresentation
bin1110110010001110101…
…01001011011101110001
31210120020121000220020112
413121013111023131301
531310342214001444
61025212344351105
751462533123222
oct7310725133561
91716217026215
10508002875249
1118649641a091
1282555175495
1338b9b15980c
141a832039249
15d3334ea69e
hex764754b771

508002875249 has 2 divisors, whose sum is σ = 508002875250. Its totient is φ = 508002875248.

The previous prime is 508002875231. The next prime is 508002875251. The reversal of 508002875249 is 942578200805.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 373712142400 + 134290732849 = 611320^2 + 366457^2 .

It is a cyclic number.

It is not a de Polignac number, because 508002875249 - 224 = 507986098033 is a prime.

It is a super-2 number, since 2×5080028752492 (a number of 24 digits) contains 22 as substring.

Together with 508002875251, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 508002875197 and 508002875206.

It is not a weakly prime, because it can be changed into another prime (508002875269) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 254001437624 + 254001437625.

It is an arithmetic number, because the mean of its divisors is an integer number (254001437625).

Almost surely, 2508002875249 is an apocalyptic number.

It is an amenable number.

508002875249 is a deficient number, since it is larger than the sum of its proper divisors (1).

508002875249 is an equidigital number, since it uses as much as digits as its factorization.

508002875249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1612800, while the sum is 50.

The spelling of 508002875249 in words is "five hundred eight billion, two million, eight hundred seventy-five thousand, two hundred forty-nine".