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5080205849813 is a prime number
BaseRepresentation
bin100100111101101001111…
…0111010111010011010101
3122222122220021120110021022
41021323103313113103111
51131213230144143223
614445451522130525
71033014144144023
oct111732367272325
918878807513238
105080205849813
111689559841656
126a06b27b0a45
132ab0a4a50bb3
14137c519c7713
158c233d02ac8
hex49ed3dd74d5

5080205849813 has 2 divisors, whose sum is σ = 5080205849814. Its totient is φ = 5080205849812.

The previous prime is 5080205849801. The next prime is 5080205849819. The reversal of 5080205849813 is 3189485020805.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4874301359524 + 205904490289 = 2207782^2 + 453767^2 .

It is a cyclic number.

It is not a de Polignac number, because 5080205849813 - 26 = 5080205849749 is a prime.

It is a super-3 number, since 3×50802058498133 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5080205849819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2540102924906 + 2540102924907.

It is an arithmetic number, because the mean of its divisors is an integer number (2540102924907).

Almost surely, 25080205849813 is an apocalyptic number.

It is an amenable number.

5080205849813 is a deficient number, since it is larger than the sum of its proper divisors (1).

5080205849813 is an equidigital number, since it uses as much as digits as its factorization.

5080205849813 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2764800, while the sum is 53.

The spelling of 5080205849813 in words is "five trillion, eighty billion, two hundred five million, eight hundred forty-nine thousand, eight hundred thirteen".