Base | Representation |
---|---|
bin | 100100111101101001111… |
… | …0111010111010011010101 |
3 | 122222122220021120110021022 |
4 | 1021323103313113103111 |
5 | 1131213230144143223 |
6 | 14445451522130525 |
7 | 1033014144144023 |
oct | 111732367272325 |
9 | 18878807513238 |
10 | 5080205849813 |
11 | 1689559841656 |
12 | 6a06b27b0a45 |
13 | 2ab0a4a50bb3 |
14 | 137c519c7713 |
15 | 8c233d02ac8 |
hex | 49ed3dd74d5 |
5080205849813 has 2 divisors, whose sum is σ = 5080205849814. Its totient is φ = 5080205849812.
The previous prime is 5080205849801. The next prime is 5080205849819. The reversal of 5080205849813 is 3189485020805.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4874301359524 + 205904490289 = 2207782^2 + 453767^2 .
It is a cyclic number.
It is not a de Polignac number, because 5080205849813 - 26 = 5080205849749 is a prime.
It is a super-3 number, since 3×50802058498133 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5080205849819) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2540102924906 + 2540102924907.
It is an arithmetic number, because the mean of its divisors is an integer number (2540102924907).
Almost surely, 25080205849813 is an apocalyptic number.
It is an amenable number.
5080205849813 is a deficient number, since it is larger than the sum of its proper divisors (1).
5080205849813 is an equidigital number, since it uses as much as digits as its factorization.
5080205849813 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2764800, while the sum is 53.
The spelling of 5080205849813 in words is "five trillion, eighty billion, two hundred five million, eight hundred forty-nine thousand, eight hundred thirteen".
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