Base | Representation |
---|---|
bin | 100100111111111010100… |
… | …1010010011011101111111 |
3 | 200000010102112102212222111 |
4 | 1021333311022103131333 |
5 | 1131303200203232041 |
6 | 14452013303154451 |
7 | 1033245340663252 |
oct | 111776512233577 |
9 | 20003375385874 |
10 | 5085059430271 |
11 | 169061a532477 |
12 | 6a1628145a27 |
13 | 2ab6994654b2 |
14 | 138192453099 |
15 | 8c419e85981 |
hex | 49ff529377f |
5085059430271 has 2 divisors, whose sum is σ = 5085059430272. Its totient is φ = 5085059430270.
The previous prime is 5085059430247. The next prime is 5085059430287. The reversal of 5085059430271 is 1720349505805.
5085059430271 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5085059430271 is a prime.
It is a super-2 number, since 2×50850594302712 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5085059430571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2542529715135 + 2542529715136.
It is an arithmetic number, because the mean of its divisors is an integer number (2542529715136).
Almost surely, 25085059430271 is an apocalyptic number.
5085059430271 is a deficient number, since it is larger than the sum of its proper divisors (1).
5085059430271 is an equidigital number, since it uses as much as digits as its factorization.
5085059430271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512000, while the sum is 49.
The spelling of 5085059430271 in words is "five trillion, eighty-five billion, fifty-nine million, four hundred thirty thousand, two hundred seventy-one".
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