Base | Representation |
---|---|
bin | 101111011010101101… |
… | …011111111001101101 |
3 | 11212102021200012120222 |
4 | 233122231133321231 |
5 | 1313232441003433 |
6 | 35220051421125 |
7 | 3451460602136 |
oct | 573255377155 |
9 | 155367605528 |
10 | 50914000493 |
11 | 1a657698164 |
12 | 9a4abb47a5 |
13 | 4a55228b15 |
14 | 266dc92c8d |
15 | 14cec39b98 |
hex | bdab5fe6d |
50914000493 has 2 divisors, whose sum is σ = 50914000494. Its totient is φ = 50914000492.
The previous prime is 50914000483. The next prime is 50914000517. The reversal of 50914000493 is 39400041905.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39195288484 + 11718712009 = 197978^2 + 108253^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50914000493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50914000463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25457000246 + 25457000247.
It is an arithmetic number, because the mean of its divisors is an integer number (25457000247).
Almost surely, 250914000493 is an apocalyptic number.
It is an amenable number.
50914000493 is a deficient number, since it is larger than the sum of its proper divisors (1).
50914000493 is an equidigital number, since it uses as much as digits as its factorization.
50914000493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 35.
The spelling of 50914000493 in words is "fifty billion, nine hundred fourteen million, four hundred ninety-three", and thus it is an aban number.
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