Base | Representation |
---|---|
bin | 10111001010101101011010… |
… | …11001000100010001101111 |
3 | 20200101100021121120012001101 |
4 | 23211112231121010101233 |
5 | 23134142404112033333 |
6 | 300204014053223531 |
7 | 13505456245043305 |
oct | 1345265531042157 |
9 | 220340247505041 |
10 | 50945516127343 |
11 | 15261965786052 |
12 | 58696ba331ba7 |
13 | 22571ac000ac6 |
14 | c81ac1a12275 |
15 | 5d532307b67d |
hex | 2e55ad64446f |
50945516127343 has 2 divisors, whose sum is σ = 50945516127344. Its totient is φ = 50945516127342.
The previous prime is 50945516127257. The next prime is 50945516127353. The reversal of 50945516127343 is 34372161554905.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50945516127343 - 245 = 15761144038511 is a prime.
It is a super-2 number, since 2×509455161273432 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50945516127353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25472758063671 + 25472758063672.
It is an arithmetic number, because the mean of its divisors is an integer number (25472758063672).
Almost surely, 250945516127343 is an apocalyptic number.
50945516127343 is a deficient number, since it is larger than the sum of its proper divisors (1).
50945516127343 is an equidigital number, since it uses as much as digits as its factorization.
50945516127343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608000, while the sum is 55.
The spelling of 50945516127343 in words is "fifty trillion, nine hundred forty-five billion, five hundred sixteen million, one hundred twenty-seven thousand, three hundred forty-three".
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