Base | Representation |
---|---|
bin | 1001011111100001… |
… | …10101101010101001 |
3 | 111011011120211012101 |
4 | 10233300311222221 |
5 | 40414123033202 |
6 | 2201411213401 |
7 | 240201554044 |
oct | 45760655251 |
9 | 14134524171 |
10 | 5096299177 |
11 | 2185801002 |
12 | ba28a7261 |
13 | 632aa7a58 |
14 | 364babc5b |
15 | 1ec629887 |
hex | 12fc35aa9 |
5096299177 has 4 divisors (see below), whose sum is σ = 5096457040. Its totient is φ = 5096141316.
The previous prime is 5096299163. The next prime is 5096299181. The reversal of 5096299177 is 7719926905.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 7719926905 = 5 ⋅1543985381.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5096299177 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5096299147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11043 + ... + 101560.
It is an arithmetic number, because the mean of its divisors is an integer number (1274114260).
Almost surely, 25096299177 is an apocalyptic number.
It is an amenable number.
5096299177 is a deficient number, since it is larger than the sum of its proper divisors (157863).
5096299177 is a wasteful number, since it uses less digits than its factorization.
5096299177 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 157862.
The product of its (nonzero) digits is 2143260, while the sum is 55.
The square root of 5096299177 is about 71388.3686394359. The cubic root of 5096299177 is about 1720.8841651443.
The spelling of 5096299177 in words is "five billion, ninety-six million, two hundred ninety-nine thousand, one hundred seventy-seven".
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