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5100054012151 = 72293181568317
BaseRepresentation
bin100101000110111001011…
…1010000110000011110111
3200001120010112101120101221
41022031302322012003313
51132024402311342101
614502533225131211
71034316043555360
oct112156272060367
920046115346357
105100054012151
111696a145937aa
126a4511929b07
132acc18b35357
14138bb5a66b67
158c9e6579aa1
hex4a372e860f7

5100054012151 has 8 divisors (see below), whose sum is σ = 5854085705120. Its totient is φ = 4352385456288.

The previous prime is 5100054012149. The next prime is 5100054012167. The reversal of 5100054012151 is 1512104500015.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5100054012151 - 21 = 5100054012149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5100054012121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1590782556 + ... + 1590785761.

It is an arithmetic number, because the mean of its divisors is an integer number (731760713140).

Almost surely, 25100054012151 is an apocalyptic number.

5100054012151 is a deficient number, since it is larger than the sum of its proper divisors (754031692969).

5100054012151 is a wasteful number, since it uses less digits than its factorization.

5100054012151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3181568553.

The product of its (nonzero) digits is 1000, while the sum is 25.

Adding to 5100054012151 its reverse (1512104500015), we get a palindrome (6612158512166).

The spelling of 5100054012151 in words is "five trillion, one hundred billion, fifty-four million, twelve thousand, one hundred fifty-one".

Divisors: 1 7 229 1603 3181568317 22270978219 728579144593 5100054012151