Base | Representation |
---|---|
bin | 100101000110111001110… |
… | …1010100101101100101011 |
3 | 200001120011102022102200021 |
4 | 1022031303222211230223 |
5 | 1132024414040142101 |
6 | 14502534401421311 |
7 | 1034316256613143 |
oct | 112156352455453 |
9 | 20046142272607 |
10 | 5100066724651 |
11 | 1696a207868a8 |
12 | 6a451603a837 |
13 | 2acc1b666742 |
14 | 138bb7615923 |
15 | 8c9e773b5a1 |
hex | 4a373aa5b2b |
5100066724651 has 2 divisors, whose sum is σ = 5100066724652. Its totient is φ = 5100066724650.
The previous prime is 5100066724631. The next prime is 5100066724691. The reversal of 5100066724651 is 1564276600015.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5100066724651 - 29 = 5100066724139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5100066724598 and 5100066724607.
It is not a weakly prime, because it can be changed into another prime (5100066724631) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550033362325 + 2550033362326.
It is an arithmetic number, because the mean of its divisors is an integer number (2550033362326).
Almost surely, 25100066724651 is an apocalyptic number.
5100066724651 is a deficient number, since it is larger than the sum of its proper divisors (1).
5100066724651 is an equidigital number, since it uses as much as digits as its factorization.
5100066724651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 5100066724651 in words is "five trillion, one hundred billion, sixty-six million, seven hundred twenty-four thousand, six hundred fifty-one".
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