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51001112203 = 232217439661
BaseRepresentation
bin101111011111111001…
…110011011010001011
311212122100120221101121
4233133321303122023
51313422241042303
635232442500111
73453566205136
oct573771633213
9155570527347
1051001112203
111a6a1886508
129a74204637
134a6a2a9202
14267b68b21d
1514d76e59bd
hexbdfe7368b

51001112203 has 4 divisors (see below), whose sum is σ = 53218551888. Its totient is φ = 48783672520.

The previous prime is 51001112179. The next prime is 51001112219. The reversal of 51001112203 is 30221110015.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 51001112203 - 25 = 51001112171 is a prime.

It is a super-3 number, since 3×510011122033 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51001119203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1108719808 + ... + 1108719853.

It is an arithmetic number, because the mean of its divisors is an integer number (13304637972).

Almost surely, 251001112203 is an apocalyptic number.

51001112203 is a deficient number, since it is larger than the sum of its proper divisors (2217439685).

51001112203 is a wasteful number, since it uses less digits than its factorization.

51001112203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2217439684.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 51001112203 its reverse (30221110015), we get a palindrome (81222222218).

The spelling of 51001112203 in words is "fifty-one billion, one million, one hundred twelve thousand, two hundred three".

Divisors: 1 23 2217439661 51001112203