Base | Representation |
---|---|
bin | 101111011111111011… |
… | …011100101000000001 |
3 | 11212122101101211120022 |
4 | 233133323130220001 |
5 | 1313422343340134 |
6 | 35232500023225 |
7 | 3453602651453 |
oct | 573773345001 |
9 | 155571354508 |
10 | 51001543169 |
11 | 1a6a2050285 |
12 | 9a74391b15 |
13 | 4a6a3ca415 |
14 | 267b7602d3 |
15 | 14d777d52e |
hex | bdfedca01 |
51001543169 has 2 divisors, whose sum is σ = 51001543170. Its totient is φ = 51001543168.
The previous prime is 51001543163. The next prime is 51001543171. The reversal of 51001543169 is 96134510015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29794902544 + 21206640625 = 172612^2 + 145625^2 .
It is a cyclic number.
It is not a de Polignac number, because 51001543169 - 232 = 46706575873 is a prime.
It is a super-2 number, since 2×510015431692 (a number of 22 digits) contains 22 as substring.
Together with 51001543171, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (51001543163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25500771584 + 25500771585.
It is an arithmetic number, because the mean of its divisors is an integer number (25500771585).
Almost surely, 251001543169 is an apocalyptic number.
It is an amenable number.
51001543169 is a deficient number, since it is larger than the sum of its proper divisors (1).
51001543169 is an equidigital number, since it uses as much as digits as its factorization.
51001543169 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 35.
The spelling of 51001543169 in words is "fifty-one billion, one million, five hundred forty-three thousand, one hundred sixty-nine".
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