Base | Representation |
---|---|
bin | 101111011111111110… |
… | …101101110110000011 |
3 | 11212122110000101002122 |
4 | 233133332231312003 |
5 | 1313423103301011 |
6 | 35232530234455 |
7 | 3453613151054 |
oct | 573776556603 |
9 | 155573011078 |
10 | 51002400131 |
11 | 1a6a2586111 |
12 | 9a74725a2b |
13 | 4a6a63a4b7 |
14 | 267b90472b |
15 | 14d789c3db |
hex | bdffadd83 |
51002400131 has 8 divisors (see below), whose sum is σ = 53848939200. Its totient is φ = 48172081320.
The previous prime is 51002400109. The next prime is 51002400173. The reversal of 51002400131 is 13100420015.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51002400131 - 222 = 50998205827 is a prime.
It is a super-2 number, since 2×510024001312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51002400931) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4048601 + ... + 4061178.
It is an arithmetic number, because the mean of its divisors is an integer number (6731117400).
Almost surely, 251002400131 is an apocalyptic number.
51002400131 is a deficient number, since it is larger than the sum of its proper divisors (2846539069).
51002400131 is a wasteful number, since it uses less digits than its factorization.
51002400131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8110129.
The product of its (nonzero) digits is 120, while the sum is 17.
Adding to 51002400131 its reverse (13100420015), we get a palindrome (64102820146).
The spelling of 51002400131 in words is "fifty-one billion, two million, four hundred thousand, one hundred thirty-one".
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