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5100316241231 = 42731193614847
BaseRepresentation
bin100101000111000001010…
…0010011010110101001111
3200001120210210211012002002
41022032002202122311033
51132030421424204411
614503015233422515
71034325406512551
oct112160242326517
920046723735062
105100316241231
11169703960a352
126a458570aa3b
132acc5b26a0a3
14138bdc8074d1
158ca0e5c733b
hex4a38289ad4f

5100316241231 has 4 divisors (see below), whose sum is σ = 5101509860352. Its totient is φ = 5099122622112.

The previous prime is 5100316241183. The next prime is 5100316241243. The reversal of 5100316241231 is 1321426130015.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5100316241231 - 222 = 5100312046927 is a prime.

It is a super-2 number, since 2×51003162412312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5100316241194 and 5100316241203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5100316241131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596803151 + ... + 596811696.

It is an arithmetic number, because the mean of its divisors is an integer number (1275377465088).

Almost surely, 25100316241231 is an apocalyptic number.

5100316241231 is a deficient number, since it is larger than the sum of its proper divisors (1193619121).

5100316241231 is a wasteful number, since it uses less digits than its factorization.

5100316241231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1193619120.

The product of its (nonzero) digits is 4320, while the sum is 29.

The spelling of 5100316241231 in words is "five trillion, one hundred billion, three hundred sixteen million, two hundred forty-one thousand, two hundred thirty-one".

Divisors: 1 4273 1193614847 5100316241231