Base | Representation |
---|---|
bin | 10111001100011100100101… |
… | …10110000111100100110101 |
3 | 20200121001100002212022121020 |
4 | 23212032102312013210311 |
5 | 23141132122234102331 |
6 | 300251244320211353 |
7 | 13513001261122500 |
oct | 1346162266074465 |
9 | 220531302768536 |
10 | 51005200300341 |
11 | 15285202959661 |
12 | 5879196469b59 |
13 | 225ca011ab2c1 |
14 | c84944572137 |
15 | 5d6b67be5c96 |
hex | 2e6392d87935 |
51005200300341 has 24 divisors (see below), whose sum is σ = 79128518112000. Its totient is φ = 29139045550272.
The previous prime is 51005200300339. The next prime is 51005200300343. The reversal of 51005200300341 is 14300300250015.
It is an interprime number because it is at equal distance from previous prime (51005200300339) and next prime (51005200300343).
It is not a de Polignac number, because 51005200300341 - 21 = 51005200300339 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51005200300343) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 39742341 + ... + 41005658.
It is an arithmetic number, because the mean of its divisors is an integer number (3297021588000).
Almost surely, 251005200300341 is an apocalyptic number.
It is an amenable number.
51005200300341 is a deficient number, since it is larger than the sum of its proper divisors (28123317811659).
51005200300341 is a wasteful number, since it uses less digits than its factorization.
51005200300341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80752313 (or 80752306 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 24.
Adding to 51005200300341 its reverse (14300300250015), we get a palindrome (65305500550356).
The spelling of 51005200300341 in words is "fifty-one trillion, five billion, two hundred million, three hundred thousand, three hundred forty-one".
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