Base | Representation |
---|---|
bin | 100101000111001000000… |
… | …0111110100111100000111 |
3 | 200001121101200200012220212 |
4 | 1022032100013310330013 |
5 | 1132031403300320203 |
6 | 14503054014350035 |
7 | 1034334144642446 |
oct | 112162007647407 |
9 | 20047350605825 |
10 | 5100544151303 |
11 | 1697146225587 |
12 | 6a4629abb31b |
13 | 2acc96547013 |
14 | 138c20bb2d5d |
15 | 8ca245e61d8 |
hex | 4a3901f4f07 |
5100544151303 has 2 divisors, whose sum is σ = 5100544151304. Its totient is φ = 5100544151302.
The previous prime is 5100544151267. The next prime is 5100544151323. The reversal of 5100544151303 is 3031514450015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5100544151303 - 28 = 5100544151047 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5100544151303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5100544151323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550272075651 + 2550272075652.
It is an arithmetic number, because the mean of its divisors is an integer number (2550272075652).
Almost surely, 25100544151303 is an apocalyptic number.
5100544151303 is a deficient number, since it is larger than the sum of its proper divisors (1).
5100544151303 is an equidigital number, since it uses as much as digits as its factorization.
5100544151303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 5100544151303 in words is "five trillion, one hundred billion, five hundred forty-four million, one hundred fifty-one thousand, three hundred three".
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