Base | Representation |
---|---|
bin | 101111100000011111… |
… | …100010101011000001 |
3 | 11212200001012112220222 |
4 | 233200133202223001 |
5 | 1313432304130441 |
6 | 35233434512425 |
7 | 3454046250356 |
oct | 574037425301 |
9 | 155601175828 |
10 | 51011005121 |
11 | 1a6a742317a |
12 | 9a77595715 |
13 | 4a6c3610cb |
14 | 267cb0462d |
15 | 14d84ebd4b |
hex | be07e2ac1 |
51011005121 has 2 divisors, whose sum is σ = 51011005122. Its totient is φ = 51011005120.
The previous prime is 51011005063. The next prime is 51011005153. The reversal of 51011005121 is 12150011015.
51011005121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32504123521 + 18506881600 = 180289^2 + 136040^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51011005121 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 51011005121.
It is not a weakly prime, because it can be changed into another prime (51011005921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25505502560 + 25505502561.
It is an arithmetic number, because the mean of its divisors is an integer number (25505502561).
Almost surely, 251011005121 is an apocalyptic number.
It is an amenable number.
51011005121 is a deficient number, since it is larger than the sum of its proper divisors (1).
51011005121 is an equidigital number, since it uses as much as digits as its factorization.
51011005121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50, while the sum is 17.
Adding to 51011005121 its reverse (12150011015), we get a palindrome (63161016136).
The spelling of 51011005121 in words is "fifty-one billion, eleven million, five thousand, one hundred twenty-one".
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