Base | Representation |
---|---|
bin | 101111100000011111… |
… | …101110111001001101 |
3 | 11212200001022002121001 |
4 | 233200133232321031 |
5 | 1313432312231211 |
6 | 35233435540301 |
7 | 3454046546332 |
oct | 574037567115 |
9 | 155601262531 |
10 | 51011055181 |
11 | 1a6a7457849 |
12 | 9a775ba691 |
13 | 4a6c37ab28 |
14 | 267cb18989 |
15 | 14d850bac1 |
hex | be07eee4d |
51011055181 has 2 divisors, whose sum is σ = 51011055182. Its totient is φ = 51011055180.
The previous prime is 51011055169. The next prime is 51011055203. The reversal of 51011055181 is 18155011015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31155427081 + 19855628100 = 176509^2 + 140910^2 .
It is a cyclic number.
It is not a de Polignac number, because 51011055181 - 223 = 51002666573 is a prime.
It is a super-2 number, since 2×510110551812 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51011055481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25505527590 + 25505527591.
It is an arithmetic number, because the mean of its divisors is an integer number (25505527591).
Almost surely, 251011055181 is an apocalyptic number.
It is an amenable number.
51011055181 is a deficient number, since it is larger than the sum of its proper divisors (1).
51011055181 is an equidigital number, since it uses as much as digits as its factorization.
51011055181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1000, while the sum is 28.
Adding to 51011055181 its reverse (18155011015), we get a palindrome (69166066196).
The spelling of 51011055181 in words is "fifty-one billion, eleven million, fifty-five thousand, one hundred eighty-one".
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