Base | Representation |
---|---|
bin | 101111100000100000… |
… | …110110000001101101 |
3 | 11212200001211220021011 |
4 | 233200200312001231 |
5 | 1313432401042131 |
6 | 35233450105221 |
7 | 3454052201641 |
oct | 574040660155 |
9 | 155601756234 |
10 | 51011346541 |
11 | 1a6a7636741 |
12 | 9a7771b211 |
13 | 4a6c45062c |
14 | 267cb92c21 |
15 | 14d85680b1 |
hex | be083606d |
51011346541 has 2 divisors, whose sum is σ = 51011346542. Its totient is φ = 51011346540.
The previous prime is 51011346511. The next prime is 51011346557. The reversal of 51011346541 is 14564311015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41931162441 + 9080184100 = 204771^2 + 95290^2 .
It is a cyclic number.
It is not a de Polignac number, because 51011346541 - 231 = 48863862893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51011346511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25505673270 + 25505673271.
It is an arithmetic number, because the mean of its divisors is an integer number (25505673271).
Almost surely, 251011346541 is an apocalyptic number.
It is an amenable number.
51011346541 is a deficient number, since it is larger than the sum of its proper divisors (1).
51011346541 is an equidigital number, since it uses as much as digits as its factorization.
51011346541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 51011346541 its reverse (14564311015), we get a palindrome (65575657556).
The spelling of 51011346541 in words is "fifty-one billion, eleven million, three hundred forty-six thousand, five hundred forty-one".
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