Base | Representation |
---|---|
bin | 10111001100101001101000… |
… | …01111110111101010101001 |
3 | 20200121201102010221221101011 |
4 | 23212110310033313222221 |
5 | 23141240443001244433 |
6 | 300254403235423521 |
7 | 13513336643301001 |
oct | 1346246417675251 |
9 | 220551363857334 |
10 | 51012203149993 |
11 | 1528817687a208 |
12 | 587a60b754ba1 |
13 | 2260578c71317 |
14 | c8500a631001 |
15 | 5d6e278c43cd |
hex | 2e65343f7aa9 |
51012203149993 has 2 divisors, whose sum is σ = 51012203149994. Its totient is φ = 51012203149992.
The previous prime is 51012203149969. The next prime is 51012203150009. The reversal of 51012203149993 is 39994130221015.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32296170752784 + 18716032397209 = 5682972^2 + 4326203^2 .
It is a cyclic number.
It is not a de Polignac number, because 51012203149993 - 25 = 51012203149961 is a prime.
It is not a weakly prime, because it can be changed into another prime (51012203149903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25506101574996 + 25506101574997.
It is an arithmetic number, because the mean of its divisors is an integer number (25506101574997).
Almost surely, 251012203149993 is an apocalyptic number.
It is an amenable number.
51012203149993 is a deficient number, since it is larger than the sum of its proper divisors (1).
51012203149993 is an equidigital number, since it uses as much as digits as its factorization.
51012203149993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 524880, while the sum is 49.
The spelling of 51012203149993 in words is "fifty-one trillion, twelve billion, two hundred three million, one hundred forty-nine thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •