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5101314230114 = 22550657115057
BaseRepresentation
bin100101000111011111000…
…0001011100011101100010
3200001200101100201021110022
41022032332001130131202
51132034442420330424
614503302244033442
71034362215336254
oct112167601343542
920050340637408
105101314230114
11169750098a153
126a4803992882
132b0089c51a5b
14138c9518dcd4
158ca6c00c95e
hex4a3be05c762

5101314230114 has 4 divisors (see below), whose sum is σ = 7651971345174. Its totient is φ = 2550657115056.

The previous prime is 5101314230107. The next prime is 5101314230119. The reversal of 5101314230114 is 4110324131015.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3116548890625 + 1984765339489 = 1765375^2 + 1408817^2 .

It is not an unprimeable number, because it can be changed into a prime (5101314230119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275328557527 + ... + 1275328557530.

Almost surely, 25101314230114 is an apocalyptic number.

5101314230114 is a deficient number, since it is larger than the sum of its proper divisors (2550657115060).

5101314230114 is a wasteful number, since it uses less digits than its factorization.

5101314230114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2550657115059.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 5101314230114 its reverse (4110324131015), we get a palindrome (9211638361129).

Subtracting from 5101314230114 its reverse (4110324131015), we obtain a palindrome (990990099099).

The spelling of 5101314230114 in words is "five trillion, one hundred one billion, three hundred fourteen million, two hundred thirty thousand, one hundred fourteen".

Divisors: 1 2 2550657115057 5101314230114