Base | Representation |
---|---|
bin | 100101000111011111000… |
… | …0001011100011101100011 |
3 | 200001200101100201021110100 |
4 | 1022032332001130131203 |
5 | 1132034442420330430 |
6 | 14503302244033443 |
7 | 1034362215336255 |
oct | 112167601343543 |
9 | 20050340637410 |
10 | 5101314230115 |
11 | 169750098a154 |
12 | 6a4803992883 |
13 | 2b0089c51a5c |
14 | 138c9518dcd5 |
15 | 8ca6c00c960 |
hex | 4a3be05c763 |
5101314230115 has 48 divisors (see below), whose sum is σ = 8870095724256. Its totient is φ = 2712153024000.
The previous prime is 5101314230107. The next prime is 5101314230119. The reversal of 5101314230115 is 5110324131015.
5101314230115 is a `hidden beast` number, since 5 + 1 + 0 + 1 + 314 + 230 + 115 = 666.
It is not a de Polignac number, because 5101314230115 - 23 = 5101314230107 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5101314230119) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 21495805 + ... + 21731825.
It is an arithmetic number, because the mean of its divisors is an integer number (184793660922).
Almost surely, 25101314230115 is an apocalyptic number.
5101314230115 is a deficient number, since it is larger than the sum of its proper divisors (3768781494141).
5101314230115 is a wasteful number, since it uses less digits than its factorization.
5101314230115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 237540 (or 237537 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 27.
The spelling of 5101314230115 in words is "five trillion, one hundred one billion, three hundred fourteen million, two hundred thirty thousand, one hundred fifteen".
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