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51014081 is a prime number
BaseRepresentation
bin1100001010011…
…0100111000001
310112222210011102
43002212213001
5101024422311
65021224145
71156420046
oct302464701
9115883142
1051014081
11268836a8
1215102055
13a751b61
146abd1cd
15472a43b
hex30a69c1

51014081 has 2 divisors, whose sum is σ = 51014082. Its totient is φ = 51014080.

The previous prime is 51014077. The next prime is 51014087. The reversal of 51014081 is 18041015.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39891856 + 11122225 = 6316^2 + 3335^2 .

It is a cyclic number.

It is not a de Polignac number, because 51014081 - 22 = 51014077 is a prime.

It is a super-2 number, since 2×510140812 = 5204872920549122, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (51014087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25507040 + 25507041.

It is an arithmetic number, because the mean of its divisors is an integer number (25507041).

Almost surely, 251014081 is an apocalyptic number.

It is an amenable number.

51014081 is a deficient number, since it is larger than the sum of its proper divisors (1).

51014081 is an equidigital number, since it uses as much as digits as its factorization.

51014081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 160, while the sum is 20.

The square root of 51014081 is about 7142.4142276964. The cubic root of 51014081 is about 370.8771034590.

Adding to 51014081 its reverse (18041015), we get a palindrome (69055096).

The spelling of 51014081 in words is "fifty-one million, fourteen thousand, eighty-one".