Base | Representation |
---|---|
bin | 101111100000101011… |
… | …010110110001100001 |
3 | 11212200021000220012101 |
4 | 233200223112301201 |
5 | 1313434102231423 |
6 | 35234025130401 |
7 | 3454114466452 |
oct | 574053266141 |
9 | 155607026171 |
10 | 51014102113 |
11 | 1a6a9148a77 |
12 | 9a78629a01 |
13 | 4a6cba6950 |
14 | 267d2ad129 |
15 | 14d890e7ad |
hex | be0ad6c61 |
51014102113 has 12 divisors (see below), whose sum is σ = 56310927484. Its totient is φ = 45941385600.
The previous prime is 51014102089. The next prime is 51014102123. The reversal of 51014102113 is 31120141015.
51014102113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 6 ways, for example, as 33126912064 + 17887190049 = 182008^2 + 133743^2 .
It is not a de Polignac number, because 51014102113 - 29 = 51014101601 is a prime.
It is a super-2 number, since 2×510141021132 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51014102123) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1145358 + ... + 1189063.
Almost surely, 251014102113 is an apocalyptic number.
It is an amenable number.
51014102113 is a deficient number, since it is larger than the sum of its proper divisors (5296825371).
51014102113 is a wasteful number, since it uses less digits than its factorization.
51014102113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2334516 (or 2334475 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 51014102113 its reverse (31120141015), we get a palindrome (82134243128).
The spelling of 51014102113 in words is "fifty-one billion, fourteen million, one hundred two thousand, one hundred thirteen".
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