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51019931 is a prime number
BaseRepresentation
bin1100001010100…
…0000010011011
310120000002012002
43002220002123
5101030114211
65021311215
71156443104
oct302500233
9116002162
1051019931
1126888036
121510550b
13a754711
146ac13ab
15472c03b
hex30a809b

51019931 has 2 divisors, whose sum is σ = 51019932. Its totient is φ = 51019930.

The previous prime is 51019889. The next prime is 51019933. The reversal of 51019931 is 13991015.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51019931 - 210 = 51018907 is a prime.

It is a super-2 number, since 2×510199312 = 5206066718489522, which contains 22 as substring.

Together with 51019933, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 51019894 and 51019903.

It is not a weakly prime, because it can be changed into another prime (51019933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25509965 + 25509966.

It is an arithmetic number, because the mean of its divisors is an integer number (25509966).

Almost surely, 251019931 is an apocalyptic number.

51019931 is a deficient number, since it is larger than the sum of its proper divisors (1).

51019931 is an equidigital number, since it uses as much as digits as its factorization.

51019931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1215, while the sum is 29.

The square root of 51019931 is about 7142.8237413505. The cubic root of 51019931 is about 370.8912795981.

The spelling of 51019931 in words is "fifty-one million, nineteen thousand, nine hundred thirty-one".