Base | Representation |
---|---|
bin | 1001100000001110… |
… | …00110000011111001 |
3 | 111011120120020101022 |
4 | 10300013012003321 |
5 | 40422121232442 |
6 | 2202140232225 |
7 | 240302263526 |
oct | 46007060371 |
9 | 14146506338 |
10 | 5102133497 |
11 | 218902645a |
12 | ba483b675 |
13 | 63406b506 |
14 | 36588a14d |
15 | 1ecdcd3d2 |
hex | 1301c60f9 |
5102133497 has 2 divisors, whose sum is σ = 5102133498. Its totient is φ = 5102133496.
The previous prime is 5102133469. The next prime is 5102133499. The reversal of 5102133497 is 7943312015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4869387961 + 232745536 = 69781^2 + 15256^2 .
It is a cyclic number.
It is not a de Polignac number, because 5102133497 - 210 = 5102132473 is a prime.
Together with 5102133499, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5102133499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2551066748 + 2551066749.
It is an arithmetic number, because the mean of its divisors is an integer number (2551066749).
Almost surely, 25102133497 is an apocalyptic number.
It is an amenable number.
5102133497 is a deficient number, since it is larger than the sum of its proper divisors (1).
5102133497 is an equidigital number, since it uses as much as digits as its factorization.
5102133497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 35.
The square root of 5102133497 is about 71429.2201903395. The cubic root of 5102133497 is about 1721.5406127352.
The spelling of 5102133497 in words is "five billion, one hundred two million, one hundred thirty-three thousand, four hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •