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51022545113 = 182327988231
BaseRepresentation
bin101111100001001011…
…100100000011011001
311212200211220211211002
4233201023210003121
51313443232420423
635234530114345
73454246322561
oct574113440331
9155624824732
1051022545113
111a702995361
129a7b41b9b5
134a718718c7
142680469da1
1514d952b228
hexbe12e40d9

51022545113 has 4 divisors (see below), whose sum is σ = 51050535168. Its totient is φ = 50994555060.

The previous prime is 51022545089. The next prime is 51022545139. The reversal of 51022545113 is 31154522015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51022545113 - 216 = 51022479577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51022515113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13992293 + ... + 13995938.

It is an arithmetic number, because the mean of its divisors is an integer number (12762633792).

Almost surely, 251022545113 is an apocalyptic number.

It is an amenable number.

51022545113 is a deficient number, since it is larger than the sum of its proper divisors (27990055).

51022545113 is a wasteful number, since it uses less digits than its factorization.

51022545113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27990054.

The product of its (nonzero) digits is 6000, while the sum is 29.

The spelling of 51022545113 in words is "fifty-one billion, twenty-two million, five hundred forty-five thousand, one hundred thirteen".

Divisors: 1 1823 27988231 51022545113