Base | Representation |
---|---|
bin | 10111001100111111101010… |
… | …10111111011011111010011 |
3 | 20200122211221121021202021111 |
4 | 23212133311113323133103 |
5 | 23141434204444400313 |
6 | 300304041154434151 |
7 | 13514236052124646 |
oct | 1346376527733723 |
9 | 220584847252244 |
10 | 51024033200083 |
11 | 15292197602a09 |
12 | 5880971592957 |
13 | 2261712b40568 |
14 | c8580d84da5d |
15 | 5d73bb27443d |
hex | 2e67f55fb7d3 |
51024033200083 has 2 divisors, whose sum is σ = 51024033200084. Its totient is φ = 51024033200082.
The previous prime is 51024033199969. The next prime is 51024033200113. The reversal of 51024033200083 is 38000233042015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51024033200083 - 29 = 51024033199571 is a prime.
It is a super-2 number, since 2×510240332000832 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51024033200683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25512016600041 + 25512016600042.
It is an arithmetic number, because the mean of its divisors is an integer number (25512016600042).
Almost surely, 251024033200083 is an apocalyptic number.
51024033200083 is a deficient number, since it is larger than the sum of its proper divisors (1).
51024033200083 is an equidigital number, since it uses as much as digits as its factorization.
51024033200083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 51024033200083 its reverse (38000233042015), we get a palindrome (89024266242098).
The spelling of 51024033200083 in words is "fifty-one trillion, twenty-four billion, thirty-three million, two hundred thousand, eighty-three".
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