Base | Representation |
---|---|
bin | 10111001100111111101010… |
… | …10111111011011111110001 |
3 | 20200122211221121021202022121 |
4 | 23212133311113323133301 |
5 | 23141434204444400423 |
6 | 300304041154434241 |
7 | 13514236052125021 |
oct | 1346376527733761 |
9 | 220584847252277 |
10 | 51024033200113 |
11 | 15292197602a36 |
12 | 5880971592981 |
13 | 2261712b4058c |
14 | c8580d84da81 |
15 | 5d73bb27445d |
hex | 2e67f55fb7f1 |
51024033200113 has 2 divisors, whose sum is σ = 51024033200114. Its totient is φ = 51024033200112.
The previous prime is 51024033200083. The next prime is 51024033200141. The reversal of 51024033200113 is 31100233042015.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 35423839914849 + 15600193285264 = 5951793^2 + 3949708^2 .
It is a cyclic number.
It is not a de Polignac number, because 51024033200113 - 213 = 51024033191921 is a prime.
It is not a weakly prime, because it can be changed into another prime (51024033270113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25512016600056 + 25512016600057.
It is an arithmetic number, because the mean of its divisors is an integer number (25512016600057).
Almost surely, 251024033200113 is an apocalyptic number.
It is an amenable number.
51024033200113 is a deficient number, since it is larger than the sum of its proper divisors (1).
51024033200113 is an equidigital number, since it uses as much as digits as its factorization.
51024033200113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 51024033200113 its reverse (31100233042015), we get a palindrome (82124266242128).
The spelling of 51024033200113 in words is "fifty-one trillion, twenty-four billion, thirty-three million, two hundred thousand, one hundred thirteen".
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