Base | Representation |
---|---|
bin | 101111100001010100… |
… | …101010101001101111 |
3 | 11212201000102002020112 |
4 | 233201110222221233 |
5 | 1313444340301224 |
6 | 35235053210235 |
7 | 3454305522026 |
oct | 574124525157 |
9 | 155630362215 |
10 | 51024931439 |
11 | 1a704275229 |
12 | 9a8019097b |
13 | 4a721c8b31 |
14 | 26808cb8bd |
15 | 14d984d30e |
hex | be152aa6f |
51024931439 has 2 divisors, whose sum is σ = 51024931440. Its totient is φ = 51024931438.
The previous prime is 51024931429. The next prime is 51024931453. The reversal of 51024931439 is 93413942015.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51024931439 - 24 = 51024931423 is a prime.
It is a super-2 number, since 2×510249314392 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51024931396 and 51024931405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51024931429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25512465719 + 25512465720.
It is an arithmetic number, because the mean of its divisors is an integer number (25512465720).
Almost surely, 251024931439 is an apocalyptic number.
51024931439 is a deficient number, since it is larger than the sum of its proper divisors (1).
51024931439 is an equidigital number, since it uses as much as digits as its factorization.
51024931439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 41.
The spelling of 51024931439 in words is "fifty-one billion, twenty-four million, nine hundred thirty-one thousand, four hundred thirty-nine".
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