Base | Representation |
---|---|
bin | 100101001000000010110… |
… | …0110100110010100010111 |
3 | 200001210111001110102210021 |
4 | 1022100011212212110113 |
5 | 1132044422334332101 |
6 | 14504021344010011 |
7 | 1034434040114554 |
oct | 112200546462427 |
9 | 20053431412707 |
10 | 5102515152151 |
11 | 1697a678656aa |
12 | 6a4a9a000907 |
13 | 2b021b9a9b01 |
14 | 138d6a87da2b |
15 | 8cadc67b5a1 |
hex | 4a4059a6517 |
5102515152151 has 4 divisors (see below), whose sum is σ = 5240420967112. Its totient is φ = 4964609337192.
The previous prime is 5102515152109. The next prime is 5102515152167. The reversal of 5102515152151 is 1512515152015.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5102515152151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5102515152181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68952907425 + ... + 68952907498.
It is an arithmetic number, because the mean of its divisors is an integer number (1310105241778).
Almost surely, 25102515152151 is an apocalyptic number.
5102515152151 is a deficient number, since it is larger than the sum of its proper divisors (137905814961).
5102515152151 is a wasteful number, since it uses less digits than its factorization.
5102515152151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137905814960.
The product of its (nonzero) digits is 12500, while the sum is 34.
The spelling of 5102515152151 in words is "five trillion, one hundred two billion, five hundred fifteen million, one hundred fifty-two thousand, one hundred fifty-one".
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