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5103000110111 = 25212024196791
BaseRepresentation
bin100101001000010001010…
…0000100100010000011111
3200001211201211222212001012
41022100202200210100133
51132101421012010421
614504141430205435
71034452046152301
oct112204240442037
920054654885035
105103000110111
111698196588802
126a4bb44b387b
132b02982c6397
14138db503b971
158cb1a02295b
hex4a42282441f

5103000110111 has 4 divisors (see below), whose sum is σ = 5105024309424. Its totient is φ = 5100975910800.

The previous prime is 5103000110107. The next prime is 5103000110167. The reversal of 5103000110111 is 1110110003015.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5103000110111 - 22 = 5103000110107 is a prime.

It is a super-2 number, since 2×51030001101112 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5103000115111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1012095875 + ... + 1012100916.

It is an arithmetic number, because the mean of its divisors is an integer number (1276256077356).

Almost surely, 25103000110111 is an apocalyptic number.

5103000110111 is a deficient number, since it is larger than the sum of its proper divisors (2024199313).

5103000110111 is a wasteful number, since it uses less digits than its factorization.

5103000110111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2024199312.

The product of its (nonzero) digits is 15, while the sum is 14.

Adding to 5103000110111 its reverse (1110110003015), we get a palindrome (6213110113126).

The spelling of 5103000110111 in words is "five trillion, one hundred three billion, one hundred ten thousand, one hundred eleven".

Divisors: 1 2521 2024196791 5103000110111