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51040033 = 114640003
BaseRepresentation
bin1100001010110…
…0111100100001
310120001002202121
43002230330201
5101031240113
65021544241
71156555522
oct302547441
9116032677
1051040033
11268a1150
1215115081
13a760905
146ac8849
154732e8d
hex30acf21

51040033 has 4 divisors (see below), whose sum is σ = 55680048. Its totient is φ = 46400020.

The previous prime is 51040021. The next prime is 51040037. The reversal of 51040033 is 33004015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51040033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51039989 and 51040016.

It is not an unprimeable number, because it can be changed into a prime (51040037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2319991 + ... + 2320012.

It is an arithmetic number, because the mean of its divisors is an integer number (13920012).

Almost surely, 251040033 is an apocalyptic number.

It is an amenable number.

51040033 is a deficient number, since it is larger than the sum of its proper divisors (4640015).

51040033 is a wasteful number, since it uses less digits than its factorization.

51040033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4640014.

The product of its (nonzero) digits is 180, while the sum is 16.

The square root of 51040033 is about 7144.2307493529. The cubic root of 51040033 is about 370.9399839468.

Adding to 51040033 its reverse (33004015), we get a palindrome (84044048).

The spelling of 51040033 in words is "fifty-one million, forty thousand, thirty-three".

Divisors: 1 11 4640003 51040033