Base | Representation |
---|---|
bin | 101111100010001111… |
… | …110101001011001001 |
3 | 11212202002121001101221 |
4 | 233202033311023021 |
5 | 1314012323103113 |
6 | 35240405442041 |
7 | 3454554406351 |
oct | 574217651311 |
9 | 155662531357 |
10 | 51040441033 |
11 | 1a711aa887a |
12 | 9a85410321 |
13 | 4a754993ca |
14 | 26829a7b61 |
15 | 14dadb398d |
hex | be23f52c9 |
51040441033 has 2 divisors, whose sum is σ = 51040441034. Its totient is φ = 51040441032.
The previous prime is 51040441031. The next prime is 51040441063. The reversal of 51040441033 is 33014404015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49065794064 + 1974646969 = 221508^2 + 44437^2 .
It is a cyclic number.
It is not a de Polignac number, because 51040441033 - 21 = 51040441031 is a prime.
Together with 51040441031, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 51040440989 and 51040441007.
It is not a weakly prime, because it can be changed into another prime (51040441031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25520220516 + 25520220517.
It is an arithmetic number, because the mean of its divisors is an integer number (25520220517).
Almost surely, 251040441033 is an apocalyptic number.
It is an amenable number.
51040441033 is a deficient number, since it is larger than the sum of its proper divisors (1).
51040441033 is an equidigital number, since it uses as much as digits as its factorization.
51040441033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 51040441033 its reverse (33014404015), we get a palindrome (84054845048).
The spelling of 51040441033 in words is "fifty-one billion, forty million, four hundred forty-one thousand, thirty-three".
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