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51042345001 is a prime number
BaseRepresentation
bin101111100010010111…
…000110000000101001
311212202020011210011021
4233202113012000221
51314013320020001
635240514332441
73454606526314
oct574227060051
9155666153137
1051042345001
111a7130892aa
129a85b8a121
134a759b4c0b
142682d4197b
1514db13cba1
hexbe25c6029

51042345001 has 2 divisors, whose sum is σ = 51042345002. Its totient is φ = 51042345000.

The previous prime is 51042344987. The next prime is 51042345019. The reversal of 51042345001 is 10054324015.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39259459600 + 11782885401 = 198140^2 + 108549^2 .

It is a cyclic number.

It is not a de Polignac number, because 51042345001 - 221 = 51040247849 is a prime.

It is a super-2 number, since 2×510423450012 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51042345301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25521172500 + 25521172501.

It is an arithmetic number, because the mean of its divisors is an integer number (25521172501).

Almost surely, 251042345001 is an apocalyptic number.

It is an amenable number.

51042345001 is a deficient number, since it is larger than the sum of its proper divisors (1).

51042345001 is an equidigital number, since it uses as much as digits as its factorization.

51042345001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 51042345001 its reverse (10054324015), we get a palindrome (61096669016).

The spelling of 51042345001 in words is "fifty-one billion, forty-two million, three hundred forty-five thousand, one".