Base | Representation |
---|---|
bin | 1001100000011110… |
… | …11111100110001001 |
3 | 111011201201002121101 |
4 | 10300033133212021 |
5 | 40423202211431 |
6 | 2202255341401 |
7 | 240330063565 |
oct | 46017374611 |
9 | 14151632541 |
10 | 5104335241 |
11 | 218a29a685 |
12 | ba5521861 |
13 | 63465c715 |
14 | 365ca06a5 |
15 | 1ed1b5961 |
hex | 1303df989 |
5104335241 has 2 divisors, whose sum is σ = 5104335242. Its totient is φ = 5104335240.
The previous prime is 5104335227. The next prime is 5104335251. The reversal of 5104335241 is 1425334015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5063745600 + 40589641 = 71160^2 + 6371^2 .
It is a cyclic number.
It is not a de Polignac number, because 5104335241 - 27 = 5104335113 is a prime.
It is not a weakly prime, because it can be changed into another prime (5104335251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552167620 + 2552167621.
It is an arithmetic number, because the mean of its divisors is an integer number (2552167621).
Almost surely, 25104335241 is an apocalyptic number.
It is an amenable number.
5104335241 is a deficient number, since it is larger than the sum of its proper divisors (1).
5104335241 is an equidigital number, since it uses as much as digits as its factorization.
5104335241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 28.
The square root of 5104335241 is about 71444.6305960077. The cubic root of 5104335241 is about 1721.7882115498.
Adding to 5104335241 its reverse (1425334015), we get a palindrome (6529669256).
The spelling of 5104335241 in words is "five billion, one hundred four million, three hundred thirty-five thousand, two hundred forty-one".
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