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51044001 = 3118114407
BaseRepresentation
bin1100001010110…
…1111010100001
310120001022012120
43002231322201
5101031402001
65022014453
71156603221
oct302557241
9116038176
1051044001
11268a4128
1215117429
13a762668
146aca081
154734236
hex30adea1

51044001 has 8 divisors (see below), whose sum is σ = 68121024. Its totient is φ = 33998160.

The previous prime is 51043999. The next prime is 51044003. The reversal of 51044001 is 10044015.

51044001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (51043999) and next prime (51044003).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 51044001 - 21 = 51043999 is a prime.

It is not an unprimeable number, because it can be changed into a prime (51044003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3661 + ... + 10746.

It is an arithmetic number, because the mean of its divisors is an integer number (8515128).

Almost surely, 251044001 is an apocalyptic number.

It is an amenable number.

51044001 is a deficient number, since it is larger than the sum of its proper divisors (17077023).

51044001 is a wasteful number, since it uses less digits than its factorization.

51044001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15591.

The product of its (nonzero) digits is 80, while the sum is 15.

The square root of 51044001 is about 7144.5084505514. The cubic root of 51044001 is about 370.9495963473.

Adding to 51044001 its reverse (10044015), we get a palindrome (61088016).

The spelling of 51044001 in words is "fifty-one million, forty-four thousand, one".

Divisors: 1 3 1181 3543 14407 43221 17014667 51044001