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5104412101 is a prime number
BaseRepresentation
bin1001100000011111…
…10010010111000101
3111011201212000001001
410300033302113011
540423212141401
62202301133301
7240330533635
oct46017622705
914151760031
105104412101
11218a3423a8
12ba555a231
136346886b9
14365cc06c5
151ed1cd601
hex1303f25c5

5104412101 has 2 divisors, whose sum is σ = 5104412102. Its totient is φ = 5104412100.

The previous prime is 5104412087. The next prime is 5104412143. The reversal of 5104412101 is 1012144015.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4812890625 + 291521476 = 69375^2 + 17074^2 .

It is a cyclic number.

It is not a de Polignac number, because 5104412101 - 217 = 5104281029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5104412191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552206050 + 2552206051.

It is an arithmetic number, because the mean of its divisors is an integer number (2552206051).

Almost surely, 25104412101 is an apocalyptic number.

It is an amenable number.

5104412101 is a deficient number, since it is larger than the sum of its proper divisors (1).

5104412101 is an equidigital number, since it uses as much as digits as its factorization.

5104412101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 160, while the sum is 19.

The square root of 5104412101 is about 71445.1684930479. The cubic root of 5104412101 is about 1721.7968536140.

Adding to 5104412101 its reverse (1012144015), we get a palindrome (6116556116).

The spelling of 5104412101 in words is "five billion, one hundred four million, four hundred twelve thousand, one hundred one".