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51044341889 is a prime number
BaseRepresentation
bin101111100010011110…
…101101100010000001
311212202100221020101002
4233202132231202001
51314014322420024
635241025221345
73454632514202
oct574236554201
9155670836332
1051044341889
111a714222622
129a86791855
134a76233ac8
1426833015a9
1514db3d46ae
hexbe27ad881

51044341889 has 2 divisors, whose sum is σ = 51044341890. Its totient is φ = 51044341888.

The previous prime is 51044341877. The next prime is 51044341921. The reversal of 51044341889 is 98814344015.

It is a happy number.

51044341889 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30828336400 + 20216005489 = 175580^2 + 142183^2 .

It is a cyclic number.

It is not a de Polignac number, because 51044341889 - 232 = 46749374593 is a prime.

It is a super-4 number, since 4×510443418894 (a number of 44 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (51044341819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25522170944 + 25522170945.

It is an arithmetic number, because the mean of its divisors is an integer number (25522170945).

Almost surely, 251044341889 is an apocalyptic number.

It is an amenable number.

51044341889 is a deficient number, since it is larger than the sum of its proper divisors (1).

51044341889 is an equidigital number, since it uses as much as digits as its factorization.

51044341889 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 552960, while the sum is 47.

The spelling of 51044341889 in words is "fifty-one billion, forty-four million, three hundred forty-one thousand, eight hundred eighty-nine".