Base | Representation |
---|---|
bin | 100101001001010101110… |
… | …1010100100111101001011 |
3 | 200002001200012220222210020 |
4 | 1022102223222210331023 |
5 | 1132121124102304003 |
6 | 14505202030551523 |
7 | 1034563060206135 |
oct | 112225352447513 |
9 | 20061605828706 |
10 | 5105301213003 |
11 | 1699167492432 |
12 | 6a55370685a3 |
13 | 2b0573c66524 |
14 | 1391528b6055 |
15 | 8cc02060d53 |
hex | 4a4abaa4f4b |
5105301213003 has 8 divisors (see below), whose sum is σ = 7207484065488. Its totient is φ = 3203326251264.
The previous prime is 5105301212971. The next prime is 5105301213013. The reversal of 5105301213003 is 3003121035015.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5105301213003 - 25 = 5105301212971 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5105301213013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50051972626 + ... + 50051972727.
It is an arithmetic number, because the mean of its divisors is an integer number (900935508186).
Almost surely, 25105301213003 is an apocalyptic number.
5105301213003 is a deficient number, since it is larger than the sum of its proper divisors (2102182852485).
5105301213003 is a wasteful number, since it uses less digits than its factorization.
5105301213003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100103945373.
The product of its (nonzero) digits is 1350, while the sum is 24.
Adding to 5105301213003 its reverse (3003121035015), we get a palindrome (8108422248018).
It can be divided in two parts, 51053012 and 13003, that added together give a palindrome (51066015).
The spelling of 5105301213003 in words is "five trillion, one hundred five billion, three hundred one million, two hundred thirteen thousand, three".
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