Base | Representation |
---|---|
bin | 101111100011000000… |
… | …001111011010111101 |
3 | 11212202222110210101111 |
4 | 233203000033122331 |
5 | 1314024100201303 |
6 | 35241541442021 |
7 | 3455100312562 |
oct | 574300173275 |
9 | 155688423344 |
10 | 51053131453 |
11 | 1a719186325 |
12 | 9a89710311 |
13 | 4a77cc072c |
14 | 268454c869 |
15 | 14dc06db6d |
hex | be300f6bd |
51053131453 has 2 divisors, whose sum is σ = 51053131454. Its totient is φ = 51053131452.
The previous prime is 51053131439. The next prime is 51053131483. The reversal of 51053131453 is 35413135015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38688136249 + 12364995204 = 196693^2 + 111198^2 .
It is a cyclic number.
It is not a de Polignac number, because 51053131453 - 229 = 50516260541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51053131483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25526565726 + 25526565727.
It is an arithmetic number, because the mean of its divisors is an integer number (25526565727).
Almost surely, 251053131453 is an apocalyptic number.
It is an amenable number.
51053131453 is a deficient number, since it is larger than the sum of its proper divisors (1).
51053131453 is an equidigital number, since it uses as much as digits as its factorization.
51053131453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 51053131453 its reverse (35413135015), we get a palindrome (86466266468).
The spelling of 51053131453 in words is "fifty-one billion, fifty-three million, one hundred thirty-one thousand, four hundred fifty-three".
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