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51054513543151 is a prime number
BaseRepresentation
bin10111001101111000011100…
…01001001101011111101111
320200202202121211102121110121
423212330032021031133233
523142434120431340101
6300330041510145411
713516365303560626
oct1346741611153757
9220682554377417
1051054513543151
11152a41089a7888
125886859352267
13226455c897511
14c870a19b46bd
155d80a21320a1
hex2e6f0e24d7ef

51054513543151 has 2 divisors, whose sum is σ = 51054513543152. Its totient is φ = 51054513543150.

The previous prime is 51054513543101. The next prime is 51054513543251. The reversal of 51054513543151 is 15134531545015.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51054513543151 - 211 = 51054513541103 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51054513543098 and 51054513543107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51054513543101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25527256771575 + 25527256771576.

It is an arithmetic number, because the mean of its divisors is an integer number (25527256771576).

Almost surely, 251054513543151 is an apocalyptic number.

51054513543151 is a deficient number, since it is larger than the sum of its proper divisors (1).

51054513543151 is an equidigital number, since it uses as much as digits as its factorization.

51054513543151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450000, while the sum is 43.

The spelling of 51054513543151 in words is "fifty-one trillion, fifty-four billion, five hundred thirteen million, five hundred forty-three thousand, one hundred fifty-one".