Base | Representation |
---|---|
bin | 10111001101111000011100… |
… | …01001001101011111101111 |
3 | 20200202202121211102121110121 |
4 | 23212330032021031133233 |
5 | 23142434120431340101 |
6 | 300330041510145411 |
7 | 13516365303560626 |
oct | 1346741611153757 |
9 | 220682554377417 |
10 | 51054513543151 |
11 | 152a41089a7888 |
12 | 5886859352267 |
13 | 226455c897511 |
14 | c870a19b46bd |
15 | 5d80a21320a1 |
hex | 2e6f0e24d7ef |
51054513543151 has 2 divisors, whose sum is σ = 51054513543152. Its totient is φ = 51054513543150.
The previous prime is 51054513543101. The next prime is 51054513543251. The reversal of 51054513543151 is 15134531545015.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51054513543151 - 211 = 51054513541103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51054513543098 and 51054513543107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51054513543101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25527256771575 + 25527256771576.
It is an arithmetic number, because the mean of its divisors is an integer number (25527256771576).
Almost surely, 251054513543151 is an apocalyptic number.
51054513543151 is a deficient number, since it is larger than the sum of its proper divisors (1).
51054513543151 is an equidigital number, since it uses as much as digits as its factorization.
51054513543151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450000, while the sum is 43.
The spelling of 51054513543151 in words is "fifty-one trillion, fifty-four billion, five hundred thirteen million, five hundred forty-three thousand, one hundred fifty-one".
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