Base | Representation |
---|---|
bin | 101111100011000111… |
… | …110011010011101011 |
3 | 11212210010012111011211 |
4 | 233203013303103223 |
5 | 1314030102112301 |
6 | 35242052133551 |
7 | 3455123206156 |
oct | 574307632353 |
9 | 155703174154 |
10 | 51055113451 |
11 | 1a71a30a441 |
12 | 9a8a3072b7 |
13 | 4a78535904 |
14 | 2684906c9d |
15 | 14dc311051 |
hex | be31f34eb |
51055113451 has 4 divisors (see below), whose sum is σ = 51532264152. Its totient is φ = 50577962752.
The previous prime is 51055113383. The next prime is 51055113457. The reversal of 51055113451 is 15431155015.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51055113451 - 27 = 51055113323 is a prime.
It is a super-2 number, since 2×510551134512 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51055113457) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 238575190 + ... + 238575403.
It is an arithmetic number, because the mean of its divisors is an integer number (12883066038).
Almost surely, 251055113451 is an apocalyptic number.
51055113451 is a deficient number, since it is larger than the sum of its proper divisors (477150701).
51055113451 is a wasteful number, since it uses less digits than its factorization.
51055113451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 477150700.
The product of its (nonzero) digits is 7500, while the sum is 31.
Adding to 51055113451 its reverse (15431155015), we get a palindrome (66486268466).
The spelling of 51055113451 in words is "fifty-one billion, fifty-five million, one hundred thirteen thousand, four hundred fifty-one".
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