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51100244989 is a prime number
BaseRepresentation
bin101111100101110011…
…111101101111111101
311212220021010102000021
4233211303331233331
51314123130314424
635250343332141
73456211626043
oct574563755775
9155807112007
1051100244989
111a742835432
129aa1451051
134a849a8071
14268a8d4393
1514e12784e4
hexbe5cfdbfd

51100244989 has 2 divisors, whose sum is σ = 51100244990. Its totient is φ = 51100244988.

The previous prime is 51100244957. The next prime is 51100245023. The reversal of 51100244989 is 98944200115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 32418002500 + 18682242489 = 180050^2 + 136683^2 .

It is a cyclic number.

It is not a de Polignac number, because 51100244989 - 25 = 51100244957 is a prime.

It is a super-2 number, since 2×511002449892 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51100244929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550122494 + 25550122495.

It is an arithmetic number, because the mean of its divisors is an integer number (25550122495).

Almost surely, 251100244989 is an apocalyptic number.

It is an amenable number.

51100244989 is a deficient number, since it is larger than the sum of its proper divisors (1).

51100244989 is an equidigital number, since it uses as much as digits as its factorization.

51100244989 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 43.

The spelling of 51100244989 in words is "fifty-one billion, one hundred million, two hundred forty-four thousand, nine hundred eighty-nine".