Base | Representation |
---|---|
bin | 101111100101110101… |
… | …000110110110010001 |
3 | 11212220021200121201121 |
4 | 233211311012312101 |
5 | 1314123214410101 |
6 | 35250354002241 |
7 | 3456214314004 |
oct | 574565066621 |
9 | 155807617647 |
10 | 51100544401 |
11 | 1a742a1a385 |
12 | 9aa1576381 |
13 | 4a84a8142a |
14 | 268a97153b |
15 | 14e12d70a1 |
hex | be5d46d91 |
51100544401 has 2 divisors, whose sum is σ = 51100544402. Its totient is φ = 51100544400.
The previous prime is 51100544393. The next prime is 51100544413. The reversal of 51100544401 is 10444500115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50894908801 + 205635600 = 225599^2 + 14340^2 .
It is a cyclic number.
It is not a de Polignac number, because 51100544401 - 23 = 51100544393 is a prime.
It is a super-2 number, since 2×511005444012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51100544461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550272200 + 25550272201.
It is an arithmetic number, because the mean of its divisors is an integer number (25550272201).
Almost surely, 251100544401 is an apocalyptic number.
It is an amenable number.
51100544401 is a deficient number, since it is larger than the sum of its proper divisors (1).
51100544401 is an equidigital number, since it uses as much as digits as its factorization.
51100544401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1600, while the sum is 25.
The spelling of 51100544401 in words is "fifty-one billion, one hundred million, five hundred forty-four thousand, four hundred one".
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