Base | Representation |
---|---|
bin | 101111100101110101… |
… | …000110110111001101 |
3 | 11212220021200121210211 |
4 | 233211311012313031 |
5 | 1314123214410321 |
6 | 35250354002421 |
7 | 3456214314121 |
oct | 574565066715 |
9 | 155807617724 |
10 | 51100544461 |
11 | 1a742a1a42a |
12 | 9aa1576411 |
13 | 4a84a81475 |
14 | 268a971581 |
15 | 14e12d70e1 |
hex | be5d46dcd |
51100544461 has 2 divisors, whose sum is σ = 51100544462. Its totient is φ = 51100544460.
The previous prime is 51100544459. The next prime is 51100544471. The reversal of 51100544461 is 16444500115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50982930436 + 117614025 = 225794^2 + 10845^2 .
It is a cyclic number.
It is not a de Polignac number, because 51100544461 - 21 = 51100544459 is a prime.
It is a super-2 number, since 2×511005444612 (a number of 22 digits) contains 22 as substring.
Together with 51100544459, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51100544401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550272230 + 25550272231.
It is an arithmetic number, because the mean of its divisors is an integer number (25550272231).
Almost surely, 251100544461 is an apocalyptic number.
It is an amenable number.
51100544461 is a deficient number, since it is larger than the sum of its proper divisors (1).
51100544461 is an equidigital number, since it uses as much as digits as its factorization.
51100544461 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
The spelling of 51100544461 in words is "fifty-one billion, one hundred million, five hundred forty-four thousand, four hundred sixty-one".
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