Base | Representation |
---|---|
bin | 10111001111001110001101… |
… | …10000011011101011001111 |
3 | 20200221011110220220122221110 |
4 | 23213213012300123223033 |
5 | 23144212421442134201 |
6 | 300403135020303103 |
7 | 13522615345363464 |
oct | 1347470660335317 |
9 | 220834426818843 |
10 | 51100560505551 |
11 | 15311698242207 |
12 | 589376a3a1a93 |
13 | 22689ba67942b |
14 | c893cd2d766b |
15 | 5d939992b6d6 |
hex | 2e79c6c1bacf |
51100560505551 has 4 divisors (see below), whose sum is σ = 68134080674072. Its totient is φ = 34067040337032.
The previous prime is 51100560505537. The next prime is 51100560505571. The reversal of 51100560505551 is 15550506500115.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 51100560505551 - 26 = 51100560505487 is a prime.
It is a super-2 number, since 2×511005605055512 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51100560505571) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8516760084256 + ... + 8516760084261.
It is an arithmetic number, because the mean of its divisors is an integer number (17033520168518).
Almost surely, 251100560505551 is an apocalyptic number.
51100560505551 is a deficient number, since it is larger than the sum of its proper divisors (17033520168521).
51100560505551 is a wasteful number, since it uses less digits than its factorization.
51100560505551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17033520168520.
The product of its (nonzero) digits is 93750, while the sum is 39.
The spelling of 51100560505551 in words is "fifty-one trillion, one hundred billion, five hundred sixty million, five hundred five thousand, five hundred fifty-one".
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