Base | Representation |
---|---|
bin | 10111001111001110001101… |
… | …10000110100001110010111 |
3 | 20200221011110221002202212121 |
4 | 23213213012300310032113 |
5 | 23144212422003343403 |
6 | 300403135022400411 |
7 | 13522615346262601 |
oct | 1347470660641627 |
9 | 220834427082777 |
10 | 51100560606103 |
11 | 15311698300808 |
12 | 589376a430107 |
13 | 22689ba6b3128 |
14 | c893cd322171 |
15 | 5d939994b3bd |
hex | 2e79c6c34397 |
51100560606103 has 4 divisors (see below), whose sum is σ = 51325673208120. Its totient is φ = 50875448004088.
The previous prime is 51100560606101. The next prime is 51100560606131. The reversal of 51100560606103 is 30160606500115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51100560606103 - 21 = 51100560606101 is a prime.
It is a super-2 number, since 2×511005606061032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51100560606101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112556300668 + ... + 112556301121.
It is an arithmetic number, because the mean of its divisors is an integer number (12831418302030).
Almost surely, 251100560606103 is an apocalyptic number.
51100560606103 is a deficient number, since it is larger than the sum of its proper divisors (225112602017).
51100560606103 is a wasteful number, since it uses less digits than its factorization.
51100560606103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 225112602016.
The product of its (nonzero) digits is 16200, while the sum is 34.
The spelling of 51100560606103 in words is "fifty-one trillion, one hundred billion, five hundred sixty million, six hundred six thousand, one hundred three".
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